Table 1 The code rate for a different number of relays

1

3

2

0.5+log₂ M ₂

4

4

1+log₂ M ₂

5

8

1.5+log₂ M ₂

\(\frac {3}{4}\)

4

4

\(0.5 + \frac {3}{4}\text {log}_{2}M_{2} \)

5

8

\(\frac {3}{4}+\frac {3}{4}\text {log}_{2}M_{2}\)

6

16

\(1+\frac {3}{4}\text {log}_{2}M_{2}\)